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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

What is the activation energy for a reaction if its rate doubles when temperature is raised from 20°C to 35°C?
$(R = 8.314$ $J m o l^{- 1} K^{- 1})$

Options:

Answer:

Solution:

Using Arrhenius equation $l o g_{10} \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 R} [\frac{1}{T_{1}} - \frac{1}{T_{2}}]$
$l o g_{10} 2 = \frac{E_{a}}{2.303 \times 8.314} \times [\frac{1}{293} - \frac{1}{308}]$
On solving $E_{a} = 34.67 kJ$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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