For the reaction : a A ⟶ b B , it is given that log ⁡ - d A d t = log ⁡ d B d t + 0.6020 . What is a : b is?

a A ⟶ b B - 1 a dA dt = 1 b dB dt or - d A d t = a b × d b d t log ⁡ - d A d t = log ⁡ a b + log ⁡ d B d t Given : log ⁡ - d A d t = log ⁡ d B d t + 0.6020 ∴ log ⁡ a b = 0.6020 = 2 × 0.3010 = 2 × log ⁡ 2 = log ⁡ 4 ∴ a : b = 4

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ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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For the reaction : $a A ⟶ b B$ , it is given that

$\log [\frac{- d A}{d t}] = \log [\frac{d B}{d t}] + 0.6020$ . What is $a : b$ is?

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Answer:

Solution:

$a A ⟶ b B$

$- \frac{1}{a} (\frac{dA}{dt}) = \frac{1}{b} (\frac{dB}{dt})$ or $\frac{- d A}{d t} = \frac{a}{b} \times \frac{d b}{d t}$

$\log (\frac{- d A}{d t}) = \log (\frac{a}{b}) + \log (\frac{d B}{d t})$

Given : $\log (\frac{- d A}{d t}) = \log (\frac{d B}{d t}) + 0.6020$

$∴ \log (\frac{a}{b}) = 0.6020 = 2 \times 0.3010$

$= 2 \times \log 2 = \log 4$

$∴ a : b = 4$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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