For a gaseous reaction, the rate is expressed in terms of d P d t in place of d C d t or d n d t , where C is concentration, n is number of moles and ′ P ′ is pressure of reactant. The three are related as -

R a t e = d C d t C = n V and C = P R T d C d t = d d t n V = 1 V × d n d t d d t P R T = 1 R T × d P d t

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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

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For a gaseous reaction, the rate is expressed in terms of $\frac{d P}{d t}$ in place of $\frac{d C}{d t}$ or $\frac{d n}{d t}$ , where $C$ is concentration, $n$ is number of moles and $' P'$ is pressure of reactant. The three are related as -

Options:

Answer:

Solution:

$R a t e = \frac{d C}{d t}$

$C = \frac{n}{V}$ and $C = \frac{P}{R T}$

$\frac{d C}{d t} = \frac{d}{d t} (\frac{n}{V}) = \frac{1}{V} \times (\frac{d n}{d t})$

$\frac{d}{d t} (\frac{P}{R T}) = \frac{1}{R T} \times (\frac{d P}{d t})$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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