For a photochemical reaction A → B , 1.0 × 1 0 - 5 mole of B were formed on absorbing 1.2 × 1 0 19 quanta each of λ = 360 nm. The quantum efficiency is given by

Number of mol of A reacted = 1 × 1 0 - 5 Number of molecules of A = 1 × 1 0 - 5 × 6.02 × 1 0 23 Quantum efficiency = 6.02 × 1 0 18 1.2 × 1 0 19 = 0.50

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ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

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For a photochemical reaction $A \to B, 1.0 \times 1 0^{- 5}$ mole of B were formed on absorbing $1.2 \times 1 0^{19}$ quanta each of $λ = 360$ nm. The quantum efficiency is given by

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Answer:

Solution:

Number of mol of A reacted $= 1 \times 1 0^{- 5}$
Number of molecules of A $= 1 \times 1 0^{- 5} \times 6.02 \times 1 0^{23}$
Quantum efficiency $= \frac{6.02 \times 1 0^{18}}{1.2 \times 1 0^{19}} = 0.50$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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