Chemistry - Chemical Kinetics Question with Solution | TestHub

$\text{t}\text{=}\frac{\text{2}\text{.303}\text{×}{\text{t}}_{\text{1/2}}}{\text{0}\text{.693}}\text{log}\frac{{\text{N}}_{\text{o}}}{\text{N}}$
${\text{t}}_{\text{1/2}}\text{=}\frac{\text{4}\text{.2}\text{×}\text{0}\text{.693}}{\text{2}\text{.303}\text{×}\text{log}\left(\frac{{\text{N}}_{\text{0}}}{\text{0}\text{.796}{\text{N}}_{\text{0}}}\right)}$
$\therefore {\text{t}}_{\text{1/2}}=12.83$