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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020

ChemistryEasysingle choice

A first order reaction has a specific reaction rate of $1 0^{- 2} s e c^{- 1}$ . How much time will it take for 20 g of the reactant to reduce to 5 g?

Options:

Answer:

Solution:

It is based on first order kinetics so using the given relation
$K = \frac{2.303}{t} l o g_{10} \frac{N_{0}}{N_{T}}$
$t = \frac{2.303}{1 0^{- 2}} \times l o g_{10} (\frac{20}{5})$
On solving $t = 138.87$ sec.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law

⏱ 2mℹ️ Source: PYQ_2020

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