Chemistry - Chemical Kinetics Question with Solution | TestHub

${\text{t}}_{\frac{1}{2}}\propto {\left(\frac{1}{\text{a}}\right)}^{\text{n}-1}$for nth order reaction.

${\text{t}}_{\frac{1}{2}}=\text{k}{\left(\text{a}\right)}^{1-\text{n}}$

$\log {\text{t}}_{\frac{1}{2}}=\left(1-\text{n}\right)\log \text{a}+\log \text{k}$

Thus, graph between$\log {\text{t}}_{\frac{1}{2}}$and$\log \text{a}$is linear slope.

$\left(1-\text{n}\right)=\tan {45}^{\text{o}}$

$\mathrm{n}=0$