Chemistry - Chemical Kinetics Question with Solution | TestHub

$\text{R}={\text{K}\left[\text{A}\right]}^{1/2}{\left[\text{B}\right]}^{1/2}$

$\frac{\text{dx}}{\text{dt}}=\text{K}{\left(1-\text{x}\right)}^{1/2}{\left(1-\text{x}\right)}^{1/2}$

$\frac{\text{dx}}{\text{dt}}=\text{K}\left(1-\text{x}\right)$

Integrating on both sides

$\text{K}=\frac{\text{2.303}}{\text{t}}\text{log}\frac{1}{1-\text{x}}\text{ , }$

$\left(\therefore \left(1-x\right)=0.1Mattimet\right)$

$\Rightarrow$$\text{4.606}\times 10^{-4}=\frac{\text{2.303}}{\text{t}}log\frac{1}{\text{0.1}}=\frac{\text{2.303}}{\text{t}}$

$\Rightarrow$$2\times 10^{-4}=\frac{1}{\text{t}}$

or $\text{t}=\frac{10^4}{2}=\frac{10000}{2}=\text{5000 s}$