Chemistry - Chemical Kinetics Question with Solution | TestHub

$\ln \left(\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}\right)=-4.606+2\ln [\mathrm{A}]$
$2.303\text{log}\left(\frac{\text{d}\left[\text{B}\right]}{\text{dt}}\right)=-4.606+2\times 2.303\text{log}\left[\text{A}\right]$
$\text{log}\left(\frac{\text{d}\left[\text{B}\right]}{\text{dt}}\right)=\frac{-4.606}{2.303}+2\text{log}\left[\text{A}\right]$
$\text{log}\left(\frac{\text{d}\left[\text{B}\right]}{\text{dt}}\right)=-2+2\text{log}\left[\text{A}\right]$
$\text{log}\left(\frac{\text{d}\left[\text{B}\right]}{\text{dt}}\right)=\text{log}{10}^{-2}+\text{log}{\left[\text{A}\right]}^{\text{2}}$
$\text{log}\left(\frac{\text{d}\left[\text{B}\right]}{\text{dt}}\right)=\text{log}\left({10}^{-2}{\left[\text{A}\right]}^2\right)$
$\left(\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}\right)=\left(10^{-2}{\left[\mathrm{A}\right]}^2\right)$
Compare with$\left(\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}\right)=\mathrm{k}{\left[\mathrm{A}\right]}^{\mathrm{m}}$
$\left(\frac{\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{d}\mathrm{t}}\right)=\left(10^{-2}{\left[\mathrm{A}\right]}^2\right)$
Order = 2