Chemistry - Chemical Kinetics Question with Solution | TestHub

$\frac{\mathrm{e}}{\mathrm{m}}$for$\left(\mathrm{i}\right)$neutron$=\frac{0}{1}=0$
$\left(\mathrm{i}\mathrm{i}\right)$$\mathrm{\alpha }-$particle$=\frac{2}{4}=0.5$
$\left(\mathrm{i}\mathrm{i}\mathrm{i}\right)$Proton$=\frac{1}{1}=1$
$\left(\mathrm{i}\mathrm{v}\right)$electron$=\frac{1}{1/1837}=1837$.