Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

TheEaof reaction in the presence of catalyst is 5.25 kJ/mol and in the absence of catalyst is 8.314 kJmol-1. What is the slope of the plot of lnk vs1Tin the absence of catalyst. (R = 8.314 J  k −1 mol −1 )

Options:

Answer:
C
Solution:

ln k=lnA-EaR×1T
slope=-EaR=-8.3×1038.3=-1000

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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