Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawEasy2 minPYQ_2020
ChemistryEasysingle choice

Consider a reaction X + Y→Products. If the initial concentration of X is increased to four times of its original value, keeping the concentration of Y constant, the rate of reaction increases four-fold. When the concentration of both X and Y becomes four times their original values, the rate of reaction becomes 16 times its original value. The observed rate law is

Options:

Answer:
C
Solution:

r1=k[X]m[Y]n…(i)
r2=4r1=k[4X]m[Y]n…(ii)
r3=16r1=k[4X]m[4Y]n…(iii)
Divide equation (ii) by equation (i)
4=(4)m
(4)1=(4)m
m=1
Divide equation (iii) by equation (ii),
4=(4)n
(4)1=(4)n
n=1.
Hence rate=k[X]1[Y]1

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law
⏱ 2mℹ️ Source: PYQ_2020

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