For the reaction N 2 + 3 H 2 → 2 NH 3 The rate of change of concentration for hydrogen is 0.3 × 10 − 4 Ms − 1 The rate of change of concentration of ammonia is:

N 2 + 3 H 2 → 2 NH 3 d H 2 dt = - 0 .3 × 10 - 4 Ms - 1 Rate = - 1 3 d H 2 dt = + 1 2 d NH 3 dt = d NH 3 dt = - 2 3 d H 2 dt = - 2 3 × ( - 0.3 × 10 - 4 ) = 0 .2 × 10 − 4 Ms − 1

Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

For the reaction
$N_{2} + 3 H_{2} \to 2 {NH}_{3}$
The rate of change of concentration for hydrogen is $0.3 \times 10^{- 4} {Ms}^{- 1}$
The rate of change of concentration of ammonia is:

Options:

Answer:

Solution:

$N_{2} + 3 H_{2} \to 2 {NH}_{3}$
$\frac{d [H_{2}]}{dt} = - 0 .3 \times 10^{- 4} {Ms}^{- 1}$
$Rate = - \frac{1}{3} \frac{d [H_{2}]}{dt} = + \frac{1}{2} \frac{d [{NH}_{3}]}{dt}$
$= \frac{d [{NH}_{3}]}{dt} = - \frac{2}{3} \frac{d [H_{2}]}{dt}$
$= - \frac{2}{3} \times (- 0.3 \times 10^{- 4})$
$= 0 .2 × 10^{- 4} {Ms}^{- 1}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Chemical KineticsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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