Chemistry - Chemical Kinetics Question with Solution | TestHub

For the reaction $2\mathrm{X}\to \mathrm{B}$, follow zeroth order Rate equation is $\mathrm{Kt}=[\mathrm{A}{]}_0-[\mathrm{A}]$ For the half-life; $t=t_{1/2}$ and $[A]=0.1$ ${\mathrm{Kt}}_{12}=0.2-0.1$ $\frac{0.2-0.1}{6}=\frac{0.1}{6}{\mathrm{Mhr}}^{-1}$ $\therefore$ Time required to reach from $0.5\mathrm{M}$ to $0.2\mathrm{M}$ $\mathrm{Kt}=[\mathrm{A}{]}_0-[\mathrm{A}]$ $\frac{0.1}{6}\times \mathrm{t}=(0.5-0.2);\mathrm{t}=18$ hour