Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsRate of Reactions/Rate LawHard2 minPYQ_2019
ChemistryHardsingle choice

For the chemical reaction

2O33O2, the reaction proceeds as follows

O3O2+O (Fast)

O+O32O2, (Slow)

the rate law expression should be given as

Options:

Answer:
A
Solution:

Let k be the rate constant of given reaction

2O3k3O2

From the slowest step r=k'OO3 ... i

To eliminate O, (From fast step)

keq=O2OO3

O=keq.O3O2

Now, substituting value of O in Eq i

r=k'keqO3O3O2

Let k'keq=k

Thus, r=kO32O2-1

Stream:BITSATSubject:ChemistryTopic:Chemical KineticsSubtopic:Rate of Reactions/Rate Law
2mℹ️ Source: PYQ_2019

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