Chemistry - Chemical Kinetics Question with Solution | TestHub

$\begin{array}{rl}& \text{ (c) : Given : }{T}_1=27^{\circ }\mathrm{C}=27+273=300\mathrm{K}\\ & T_2=37^{\circ }\mathrm{C}=37+273=310\mathrm{K}\\ & \text{ and }{E}_a=53.6\mathrm{kJ}{\mathrm{mol}}^{-1}\\ & \begin{array}{r}\log \left(\frac{k_2}{k_1}\right)=\frac{E_a}{2.303R}\left(\frac{T_2-T_1}{T_1{T}_2}\right)\\ \log \left(\frac{k_{310\mathrm{K}}}{k_{300\mathrm{K}}}\right)=\frac{53.6\times 10^3}{2.303\times 8.314}\left(\frac{310-300}{300\times 310}\right)\\ =0.3010\end{array}\\ & \therefore \frac{k_{310\mathrm{K}}}{k_{300\mathrm{K}}}=2\end{array}$