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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsMedium2 minPYQ_2017

ChemistryMediumsingle choice

A first-order reaction has a specific reaction rate $10^{- 2} \sec^{- 1} .$ How much time will it take for $20 g$ the reactant to reduce to $5 g$ ?NEET 2017

Options:

Answer:

Solution:

$t_{\frac{1}{2}} = \frac{0 .693}{10^{- 2}} second$

For the reduction of $20 g$ of reactant to $5 g$ , two $t_{\frac{1}{2}}$ is required.

$∴ t = 2 \times \frac{0 .693}{10^{- 2}} second$

$= 138.6 s e c o n d$

Stream:NEETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2017

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