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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsEasy2 minPYQ_2010

ChemistryEasysingle choice

The activity of an old piece of wood is just $25%$ of the fresh piece of wood. If $t_{1/2}$ of $- 14$ is 6000 yr, the age of piece of wood is

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Answer:

Solution:

As we know that, $k t = \frac{0.693}{t _{1/2}} = \frac{0.693}{6000} = 1.155 \times 1 0^{- 4} = \frac{2.303}{k} lo g \frac{N _{0}}{N} = \frac{2.303}{1.155 \times 1 0 ^{- 4}} lo g \frac{100}{25} = 12000 yr (age of piece of wood)$

Stream:VITEEESubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2010

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