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Chemistry - Chemical Kinetics Question with Solution | TestHub

ChemistryChemical KineticsSecond & nth Order ReactionsHard2 minPYQ_2009

ChemistryHardsingle choice

An element $_{x} A^{y}$ emits $5 α$ and $4 β$ particles to give $_{82} B^{207}$ . The number of protons and neutrons in $A$ are respectively

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Answer:

Solution:

$_{x} A^{y} ⟶_{82} B^{207} + 5_{2} He^{4} + 4_{- 1} β^{0}$ On comparing, $x y = 82 + 5 \times 2 + 4 (- 1) = 88 = 207 + 5 \times 4 + 4 \times 0 = 227$ $In_{88} A^{227}$ the number of protons $= 88$ the number of neutrons $= 227 - 88$

Stream:MHT_CETSubject:ChemistryTopic:Chemical KineticsSubtopic:Second & nth Order Reactions

⏱ 2mℹ️ Source: PYQ_2009

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