Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KpMedium2 minQB
ChemistryMediumsingle choice

Options:

Answer:
A
Solution:

\begin{gathered}{}\text{NH}_{\text{2}}\text{CONH}_{\text{4}}\text{(s)}\text{ }\rightleftharpoons\text{ }\text{2NH}_{\text{3}}\text{(g)}\text{ }\text{+}\text{ }\text{CO}_{\text{2}}\text{(g)}\text{ }\text{If}\text{ }\text{fraction}\text{ }\alpha\text{ }\text{of}\text{ }\text{1}\text{ }\text{mol}\text{ }\text{dissociates:}\text{ }\text{NH}_{\text{3}}\text{ }\text{=}\text{ }\text{2}\alpha\text{,}\text{ }\text{CO}_{\text{2}}\text{ }\\{}\text{=}\text{ }\alpha\text{,}\text{ }\text{total}\text{ }\text{gas}\text{ }\text{=}\text{ }\text{3}\alpha\text{ }\text{mol}\\{}\text{PV}\text{ }\text{=}\text{ }\text{3}\alpha\text{ }\text{RT}\text{ }\text{gives}\text{ }\alpha\text{ }\text{=}\text{ }\text{PV/(3RT)}\\{}\text{Percentage}\text{ }\text{dissociation}\text{ }\text{=}\text{ }\text{100}\alpha\text{ }\text{=}\text{ }\text{100PV/3RT%}\\{}\text{This}\text{ }\text{is}\text{ }\text{option}\text{ }\text{(a).}\end{gathered}

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB

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