In an empty cylinder piston arrangement, $NO_{2} (g)$ at 2 atm and $N_{2} O_{4} (g)$ at 4 atm is taken and the constant pressure of 6 atm and temperature, $2 7^{\circ} C$ , is maintained.
Which of the following property (ies) of system will change correctly (as given) with time?

Question

In an empty cylinder piston arrangement, $NO_{2} (g)$ at 2 atm and $N_{2} O_{4} (g)$ at 4 atm is taken and the constant pressure of 6 atm and temperature, $2 7^{\circ} C$ , is maintained.

Which of the following property (ies) of system will change correctly (as given) with time?

TestHub · Accepted Answer

Given: N 2 ​ O 4 ​ ( g ) ⇌ 2 N O 2 ​ ( g ) , K P ​ = 20 a t 300 K Initial partial pressures: P N O 2 ​ ​ = 2 a t m atm, P N 2 ​ O 4 ​ ​ = 4 a t m Reaction quotient: Q p ​ = [ P N 2 ​ O 4 ​ ​ ] [ P NO 2 ​ ] 2 ​ = 4 ( 2 ) 2 ​ = 1 Since Q c ​ < K c ​ , the reaction moves forward, meaning more NO₂ is formed. Moles increase (1 → 2), so volume increases, which means density decreases. (A) NO₂ is a brown gas, so the color becomes deeper. (C) Average molar mass decreases , and the reaction does proceed.

Chemistry - Chemical Equilibrium Question with Solution | TestHub

Options:(select one or more)

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