Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KcHard2 minQB
ChemistryHardnumerical

\begin{gathered}{}\text{The}\text{ }\text{equilibrium:}\text{ }\text{p-xyloquinone}\text{ }\text{+}\text{ }\text{methylene}\text{ }\text{white}\text{ }\rightleftharpoons\text{ }\text{p-xylohydroquinone}\text{ }\text{+}\text{ }\\{}\text{methylene}\text{ }\text{blue,}\text{ }\text{may}\text{ }\text{be}\text{ }\text{studied}\text{ }\text{conveniently}\text{ }\text{by}\text{ }\text{observing}\text{ }\text{the}\text{ }\text{difference}\text{ }\text{in}\text{ }\\{}\text{colour}\text{ }\text{between}\text{ }\text{methylene}\text{ }\text{blue}\text{ }\text{and}\text{ }\text{methylene}\text{ }\text{white.}\text{ }\text{One}\text{ }\text{millimole}\text{ }\text{of}\text{ }\text{methylene}\text{ }\\{}\text{blue}\text{ }\text{was}\text{ }\text{added}\text{ }\text{to}\text{ }\text{1.00}\text{ }\text{L}\text{ }\text{of}\text{ }\text{solution}\text{ }\text{that}\text{ }\text{was}\text{ }\text{0.24}\text{ }\text{M}\text{ }\text{in}\text{ }\text{p-xylohydroquinone}\text{ }\text{and}\text{ }\\{}\text{0.012}\text{ }\text{M}\text{ }\text{in}\text{ }\text{p-xyloquinone.}\text{ }\text{It}\text{ }\text{was}\text{ }\text{then}\text{ }\text{found}\text{ }\text{that}\text{ }\text{4.0%}\text{ }\text{of}\text{ }\text{the}\text{ }\text{added}\text{ }\text{methylene}\text{ }\\{}\text{blue}\text{ }\text{was}\text{ }\text{reduced}\text{ }\text{to}\text{ }\text{methylene}\text{ }\text{white.}\text{ }\text{What}\text{ }\text{is}\text{ }\text{the}\text{ }\text{equilibrium}\text{ }\text{constant}\text{ }\text{for}\text{ }\text{the}\text{ }\\{}\text{above}\text{ }\text{reaction?}\text{ }\text{The}\text{ }\text{equation}\text{ }\text{is}\text{ }\text{balanced}\text{ }\text{with}\text{ }\text{1}\text{ }\text{molecule}\text{ }\text{of}\text{ }\text{each}\text{ }\text{of}\text{ }\text{the}\text{ }\text{four}\text{ }\\{}\text{substances.}\end{gathered}

Answer:
480.00
Solution:

\begin{gathered}{}\text{Methylene}\text{ }\text{blue}\text{ }\text{added}\text{ }\text{=}\text{ }\text{1}\text{ }\text{mmol}\text{ }\text{in}\text{ }\text{1.00}\text{ }\text{L}\text{ }\text{=}\text{ }\text{1}\text{ }\times\text{ }\text{10}^{\text{-3}}\text{ }\text{M}\text{ }\text{Methylene}\text{ }\text{blue}\text{ }\text{reduced}\text{ }\text{=}\text{ }\\{}\text{4.0%}\text{ }\text{of}\text{ }\text{10}^{\text{-3}}\text{ }\text{=}\text{ }\text{4}\text{ }\times\text{ }\text{10}^{\text{-5}}\text{ }\text{M}\\{}\text{[methylene}\text{ }\text{white]}\text{ }\text{=}\text{ }\text{4}\text{ }\times\text{ }\text{10}^{\text{-5}}\text{ }\text{M}\text{ }\text{and}\text{ }\text{[methylene}\text{ }\text{blue]}\text{ }\text{=}\text{ }\text{9.6}\text{ }\times\text{ }\text{10}^{\text{-4}}\text{ }\text{M}\\{}\text{The}\text{ }\text{change}\text{ }\text{of}\text{ }\text{4}\text{ }\times\text{ }\text{10}^{\text{-5}}\text{ }\text{M}\text{ }\text{is}\text{ }\text{negligible}\text{ }\text{against}\text{ }\text{0.24}\text{ }\text{M}\text{ }\text{and}\text{ }\text{0.012}\text{ }\text{M,}\text{ }\text{so}\text{ }\\{}\text{[hydroquinone]}\text{ }\approx\text{ }\text{0.24}\text{ }\text{M}\text{ }\text{and}\text{ }\text{[quinone]}\text{ }\approx\text{ }\text{0.012}\text{ }\text{M}\\{}\text{K}\text{ }\text{=}\text{ }\text{[hydroquinone][methylene}\text{ }\text{blue]/([quinone][methylene}\text{ }\text{white])}\\{}\text{K}\text{ }\text{=}\text{ }\text{(0.24)(9.6}\text{ }\times\text{ }\text{10}^{\text{-4}}\text{)/[(0.012)(4}\text{ }\times\text{ }\text{10}^{\text{-5}}\text{)]}\\{}\text{K}\text{ }\text{=}\text{ }\text{480,}\text{ }\text{written}\text{ }\text{as}\text{ }\text{0480}\end{gathered}

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...