Chemistry - Chemical Equilibrium Question with Solution | TestHub

$K_P=P_{H_{2}O}^y$

$$\begin{array}{rl}0.5& =P_{H_{2}O(g)}\\ MgS{O}_4\cdot 7H_2{O}_{(s)}& \rightleftharpoons MgS{O}_4\cdot x{H}_2{O}_{(s)}+y{H}_2{O}_{(g)}\\ K_p& =0.125atm\\ P_{H_{2}O}^y& =0.125\\ (0.5{)}^y& =0.125\\ \Rightarrow y& =3\\ \Rightarrow x& =4\end{array}$$