In the reaction N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) , initially 5 moles of N 2 and 10 moles of H 2 were taken. If the equilibrium pressure is 11 atm and 40% of N 2 has reacted, then K

Question

In the reaction N 2 ​ ( g ) + 3 H 2 ​ ( g ) ⇌ 2 N H 3 ​ ( g ) , initially 5 moles of N 2 ​ and 10 moles of H 2 ​ were taken. If the equilibrium pressure is 11 atm and 40% of N 2 ​ has reacted, then K p ​ (in atm − 2 ) is

TestHub · Accepted Answer

40% of 5 mol N 2 ​ reacts: x = 2 mol . N 2 ​ = 3 , H 2 ​ = 10 − 6 = 4 , N H 3 ​ = 4 . Total = 11 mol. With P = 11 atm , partial pressures equal the mole numbers: 3, 4 and 4 atm. K p ​ = ( 4 ) 2 / ( 3 × 4 3 ) = 16/192 = 1/12 atm − 2 . Trap: using 5 and 10 mol as the equilibrium amounts. Answer: (A).

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