Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KpEasy2 minQB
ChemistryEasysingle choice
What is Kp for the phosphine dissociation reaction at T?
Options:
Answer:
B
Solution:
For initially pure phosphine, Kp = 27α4P2/[16(1-α2)2]. At α = 1/2 and P = 36 atm, the equilibrium partial pressures of phosphine, diphosphorus and hydrogen are 12, 6 and 18 atm.
Kp = (6)(18)3/(12)2 = 243 atm2.
This is option (b).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp
⏱ 2mℹ️ Source: QB
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