Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumProblems involving KcHard2 minQB
ChemistryHardsingle choice
An amount of 12 moles H2 and 4 moles of N2 is confined in a vessel of volume 2 litre. The vessel is heated to a constant temperature until equilibrium is established. At equilibrium, the pressure was found to be 15/16 of the initial pressure. The value of Kc for N2(g) + 3H2(g) ⇌ 2NH3(g) is
Options:
Answer:
D
Solution:
Initial moles = 12 + 4 = 16; at constant V and T, final moles = 15/16×16 = 15 Moles decrease by 2x: 2x = 1, so x = 0.5
At equilibrium N2 = 3.5, H2 = 10.5, NH3 = 1.0 mol in 2 L, i.e. 1.75 M, 5.25 M, 0.50 M
Kc = ((0.50)2)/((1.75)(5.25)3) = 0.25/253.2
Kc = 9.87×10-4
This is option (d).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kc
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
