An amount of 4 moles of N 2 and some H 2 is introduced into an evacuated vessel. The reaction starts at t = 0 and equilibrium is attained at t = t 1 . It is observed that (w(N 2 ))/(w(H 2 )) = 14/3 at

Question

An amount of 4 moles of N 2 and some H 2 is introduced into an evacuated vessel. The reaction starts at t = 0 and equilibrium is attained at t = t 1 . It is observed that (w(N 2 ))/(w(H 2 )) = 14/3 at t = t 1 /4 and at t = t 1 /2. The value of w(N 2 ) + w(H 2 ) + w(NH 3 ) at t = 3t 1 /2 is

TestHub · Accepted Answer

N 2 and H 2 react in the mass ratio 28:6 = 14:3 The ratio w(N 2 )/w(H 2 ) stays at 14/3 at two different times only if the initial mass ratio is also 14/3 Initial N 2 = 4×28 = 112 g, so initial H 2 = 112×3/14 = 24 g Total mass is conserved at every time: 112 + 24 = 136 g This is option (c).

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