Chemistry - Chemical Equilibrium Question with Solution | TestHub
Two gases X and Y, one being the dimer of the other, are at equilibrium. Increase of pressure at constant temperature or decrease of temperature at constant pressure favours the formation of more of X. The reaction could not be represented by
Options:(select one or more)
Answer:
Solution:
High pressure favors the side with fewer moles. Therefore, X is the dimer, and Y is the monomer. Low temperature must favor X, which means the formation of X from Y must be exothermic.
(b) The reaction 2Y ⇌X + q is exothermic in the direction of X, fitting both conditions.
(d) The reaction X ⇌2Y - q is endothermic towards Y, meaning it is exothermic towards X, and thus fits both conditions.
(a) The reaction X ⇌2Y + q is exothermic towards Y. Therefore, cooling would favor Y, which does not fit the conditions.
(c) The reaction 2Y ⇌X - q is endothermic towards X. Therefore, cooling would favor Y, which does not fit the conditions.
The reactions that could not represent the system are (a) and (c).
