Chemistry - Chemical Equilibrium Question with Solution | TestHub
ChemistryChemical EquilibriumEffect of temperatureMedium2 minQB
ChemistryMediumsingle choice
Carbon dioxide decomposes at high temperature according to the equation:
2CO2(g) ⇌ 2CO(g) + O2(g); Δ H° = 510 kJ/mol and Δ S° = 120 J K-1/mol
The temperature at which the equilibrium constant (Kp°) becomes 1.0, is
Options:
Answer:
B
Solution:
Kp° = 1 means Δ G° = -RTln K = 0 Δ G° = Δ H° - TΔ S° = 0
T = Δ H°/Δ S° = 510000/120 = 4250 K
This is option (b).
Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Effect of temperature
⏱ 2mℹ️ Source: QB
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