Chemistry - Chemical Equilibrium Question with Solution | TestHub

$$\begin{array}{c}\Delta {\text{n}}_{\text{g}}\text{=}\text{3}\text{-}\text{2}\text{=}\text{1}\text{and}\text{take}\text{R}\text{=}\text{2}\text{cal/mol/K}\text{so}\text{RT}\text{=}\text{600}\text{cal/mol}\Delta {\text{H}}^{{}^{\circ }}\text{=}\Delta {\text{E}}^{{}^{\circ }}\text{+}\Delta {\text{n}}_{\text{g}}\\ \text{RT}\text{=}\text{-30000}\text{+}\text{600}\text{=}\text{-29400}\text{cal}\\ \Delta {\text{G}}^{{}^{\circ }}\text{=}\Delta {\text{H}}^{{}^{\circ }}\text{-}\text{T}\Delta {\text{S}}^{{}^{\circ }}\text{=}\text{-29400}\text{-}\text{300(-100)}\text{=}\text{+600}\text{cal}\\ \Delta {\text{G}}^{{}^{\circ }}\text{=}\text{-RTln}\text{K}\text{gives}\text{ln}\text{K}\text{=}\text{-600/600}\text{=}\text{-1}\\ \text{K}\text{=}\text{1/e}\\ \text{This}\text{is}\text{option}\text{(b).}\end{array}$$