Chemistry - Chemical Equilibrium Question with Solution | TestHub

$2\mathrm{A}\rightleftharpoons \mathrm{B}+\mathrm{C},{\mathrm{K}}_{\mathrm{C}}=4\times 10^{-3}$ At a given time $\mathrm{t},{\mathrm{Qc}}_{\mathrm{c}}$ is to be calculated and been compared with ${\mathrm{K}}_{\mathrm{c}}$. $\begin{array}{rl}& {\mathrm{Q}}_{\mathrm{C}}=\frac{[\mathrm{B}][\mathrm{C}]}{[\mathrm{A}{]}^2}=\frac{\left(2\times 10^{-3}\right)\left(2\times 10^{-3}\right)}{{\left(2\times 10^{-3}\right)}^2}\\ & {\mathrm{Q}}_{\mathrm{C}}=1\end{array}$ As $Q_c{\text{gtK}}_c$, so reaction has a tendency to move backward.