Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumProblems involving KpEasy2 minPYQ_2021

ChemistryEasynumerical

At $1990 K$ and $1 atm$ pressure, there are equal number of ${Cl}_{2}$ molecules and $Cl$ atoms in the reaction mixture. The value of $K_{p}$ for the reaction ${Cl}_{2 (g)} = 2 {Cl}_{(g)}$ under the above conditions is $x \times 10^{- 1} .$ The value of $x$ is______(Rounded off to the nearest integer)

Answer:

5.00

Solution:

${Cl}_{2} ⇌ 2 Cl$

Let mol of both of ${Cl}_{2}$ and $Cl$ is $x$

$P_{Cl} = \frac{x}{2 x} \times 1 = \frac{1}{2} atm$

$P_{{Cl}_{2}} = \frac{x}{2 x} \times 1 = \frac{1}{2} atm$

$K_{p} = \frac{{(\frac{1}{2})}^{2}}{\frac{1}{2}} = \frac{1}{2} = 0.5 \Rightarrow 5 \times 10^{- 1}$

Stream:JEESubject:ChemistryTopic:Chemical EquilibriumSubtopic:Problems involving Kp

⏱ 2mℹ️ Source: PYQ_2021

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