For the process H 2 O (l) (1 bar, 373 K) → H 2 O (g) (1 bar, 373 K), the correct set of thermodynamic parameters are

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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumLe-Chatelier's PrincipleEasy2 minPYQ_2020

ChemistryEasysingle choice

For the process
$H_{2} O$ (l) (1 bar, 373 K) $\to H_{2} O$ (g) (1 bar, 373 K), the correct set of thermodynamic parameters are

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Answer:

Solution:

$\underset{(1 b a r, 373 K)}{H_{2} O (l)} ⇌ \underset{(1 b a r, 373 K)}{H_{2} O (g)}$
At 100oC, $H_{2} O (l)$ has equilibrium with $H_{2} O (g)$ therefore $Δ G = 0$ .
As liquid molecules are converting into gases molecules therefore $Δ S =$ positive.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle

⏱ 2mℹ️ Source: PYQ_2020

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