The equilibrium constants for the reaction, B r 2 ⇌ 2 B r , at 500 K and 700 K are 1 × 1 0 - 10 and 1 × 1 0 - 5 respectively. The reaction is

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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumLe-Chatelier's PrincipleEasy2 minPYQ_2020

ChemistryEasysingle choice

The equilibrium constants for the reaction, $B r_{2} ⇌ 2 B r$ , at 500 K and 700 K are $1 \times 1 0^{- 10}$ and $1 \times 1 0^{- 5}$ respectively. The reaction is

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As the equilibrium constants for the reaction, $B r_{2} ⇌ 2 B r$ , at 500 K and 700 K are $1 \times 1 0^{- 10}$ and $1 \times 1 0^{- 5}$ respectively it means the value of equilibrium constant is increasing with increase temperature so it is an endothermic reaction.

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Le-Chatelier's Principle

⏱ 2mℹ️ Source: PYQ_2020

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