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Chemistry - Chemical Equilibrium Question with Solution | TestHub

ChemistryChemical EquilibriumMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

The equilibrium constant $K_{p}$ for a homogenous gaseous reaction is $1 0^{- 3}$ . The standard Gibbs free energy change $Δ G °$ for the reaction at $27 ° C$ (using R = 2 cal $K^{- 1} m o l^{- 1}$ ) is

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Answer:

Solution:

$ΔG = - 2 .303 RT log K_{p}$
$= - 2.303 \times 2 \times 300 log 10^{- 3}$
$= - 2 .303 × 2 × 300 × (- 3)$
$= 1445 .4 cal = 4 .1454 kcal$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Chemical EquilibriumSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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