Chemistry - Chemical Equilibrium Question with Solution | TestHub

The equilibrium constants for the reactions are
${\text{H}}_{\text{3}}{\text{PO}}_{\text{4}}\stackrel{{\text{K}}_{\text{1}}}{\rightleftharpoons }{\text{H}}^{\text{+}}\text{+}{\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}^{-}\text{;}{\text{K}}_{\text{1}}$
${\text{H}}_{\text{2}}{\text{PO}}_{\text{4}}^{-}\stackrel{{\text{K}}_{\text{2}}}{\rightleftharpoons }{\text{H}}^{\text{+}}\text{+}{\text{HPO}}_{\text{4}}^{-\text{2}}\text{;}{\text{K}}_{\text{2}}$
${\text{HPO}}_{\text{4}}^{\text{2}-}\stackrel{{\text{K}}_{\text{2}}}{\rightleftharpoons }{\text{H}}^{\text{+}}\text{+}{\text{PO}}_{\text{4}}^{\text{3}-}\text{;}{\text{K}}_{\text{3}}$
The equilibrium constant for
${\mathrm{H}}_3\mathrm{P}{\mathrm{O}}_4\rightleftharpoons 3{\mathrm{H}}^{+}+\mathrm{P}{\mathrm{O}}_4^{3-}$will be