Chemistry - Chemical Equilibrium Question with Solution | TestHub

Initially 2 moles of $\mathrm{CO}$ are present. At equilibrium, 1 mole of $\mathrm{CO}$ is present Hence, $2-1=1$ moles of $\mathrm{CO}$ has reacted. 1 mole of CO will react with 1 mole of ${\mathrm{Cl}}_2$ to form 1 mole of ${\mathrm{COCl}}_2$. $3-1=2$ moles of ${\mathrm{Cl}}_2$ remains at equilibrium The equilibrium constant $$K_{\mathrm{c}}=\frac{\left[{\mathrm{COCl}}_2\right]}{[\mathrm{CO}]\left[{\mathrm{Cl}}_2\right]}=\frac{\frac{1\mathrm{mol}}{5\mathrm{L}}}{\frac{1\mathrm{mol}}{5\mathrm{L}}\times \frac{2\mathrm{mol}}{5\mathrm{L}}}=2.5$$