Chemistry - Chemical Equilibrium Question with Solution | TestHub

$A+2B\rightleftharpoons 2C$
As 1 mole of $C$ is formed at equilibrium, $2x=1\Rightarrow x=0.5$ $\Rightarrow$ Number of moles of $A$ at equilibrium $=1.5,B=1$ and $C=1$ $\therefore$ Equilibrium concentration of $A=1.5/10$ $\begin{array}{c}B=1/10\text{ and }C=1/10\\ K_c=\frac{[C{]}^2}{[A][B{]}^2}=\frac{[1/10{]}^2}{[1.5/10][1/10{]}^2}=6.67\end{array}$