Chemistry - CHEMICAL BONDING Question with Solution | TestHub

$S{F}_6$ and $N{F}_3$ are sterically protected due to the presence of closely held F atoms around S and three F atoms around N respectively, which prevent the attack of water molecules. Also, N in $N{F}_3$ does not have d-orbitals to accept electrons from water molecules, making it inert to hydrolysis. Therefore, $S{F}_6$ and $N{F}_3$ cannot be hydrolyzed.