In a restricted local orbital-counting model, the ethyl radical carbon bearing the unpaired electron uses three sp² hybrids for σ bonds; NO₂ is drawn O=N–O with one unpaired electron on N; BrO₃ radica

Question

In a restricted local orbital-counting model, the ethyl radical carbon bearing the unpaired electron uses three sp² hybrids for σ bonds; NO₂ is drawn O=N–O with one unpaired electron on N; BrO₃ radical is drawn with three Br=O bonds and one unpaired electron on Br. Count one central orbital per σ or π bond, excluding the orbital containing the odd electron. Which central atom uses the greatest number of bonding orbitals in this declared model?

TestHub · Accepted Answer

The counts in the explicitly specified Lewis/local-orbital model are 3, 3 (two σ plus one π), and 6 (three σ plus three π). Thus BrO₃ gives the largest count. This is formal bond bookkeeping, not a claim that modern hypervalent bonding requires literal d-orbital hybridisation.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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