Among the given statements. (I) Octet completion is main driving force for ICl 3 → I 2 Cl 6 (II) If B 2 H 6 + 2 L → 2 [ H 3 B ← L ] then L can be R − NH 2 (III) Molecules Al 2 ( CH 3

Question

Among the given statements.

(I) Octet completion is main driving force for $ICl_{3} \to I_{2} Cl_{6}$

(II) If $B_{2} H_{6} + 2 L \to 2 [H_{3} B \leftarrow L]$ then L can be $R - NH_{2}$

(III) Molecules $Al_{2} (CH_{3})_{6}$ have $3 c - 2 e^{-}$ bond.

(IV) In $C ∙ F_{3}$ unpaired electrons exist in $sp^{3}$ hybrid orbital.

How many of the above statements are correct?

TestHub · Accepted Answer

Correct Statements

Statement III: In Al₂(CH₃)₆ (Trimethylaluminium dimer), the bridging methyl (-CH₃) groups form two banana-like electron-deficient $3 c - 2 e^{-}$ (3-center-2-electron) bonds connecting the two aluminum atoms.

Statement IV: Due to the high electronegativity of Fluorine atoms, the $∙ C F_{3}$ free radical adopts a pyramidal geometry (unlike the planar $∙ C H_{3}$ ). Consequently, its unpaired electron resides in an sp³ hybrid orbital.

Incorrect Statements

Statement I: In ICl₃, the central Iodine atom already contains 10 electrons in its valence shell (expanded octet). Dimerization to I₂Cl₆ expands it further to 12 electrons, meaning octet completion is not the driving force.

Statement II: Primary amines (R-NH₂) are sterically small and strong bases, causing asymmetrical cleavage of diborane (B₂H₆) to form an ionic compound $[B H_{2} (L)_{2}]^{+} [B H_{4}]^{-}$ , rather than the symmetrical product shown.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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