Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTMedium2 minQB

ChemistryMediuminteger

Find the difference of number of $π$ -bond(s) in cation and anion of $N_{2} O_{5}$ solid

Answer:

1

Solution:

N₂O₅ solid exists as [NO₂]⁺[NO₃]⁻.

In [NO₂]⁺, N has 2 $π$ -bonds.

In [NO₃]⁻, N has 1 $π$ -bond.

Difference = $∣2 - 1∣ = 1$ .

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT

⏱ 2mℹ️ Source: QB

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