Consider M.O.T. for given questions and find correct statement(s). E 2 E 2 q B.L. 121 pm 112 pm B.E. 496 pm 643 pm (I) E 2 can have ( σ 2 p ) 2 ( π 2 p ) 4 ( π ∗ 2 p ) 2 configuration (II)

Question

Consider M.O.T. for given questions and find correct statement(s).

$E_{2}$ $E_{2}^{q}$

B.L. 121 pm 112 pm

B.E. 496 pm 643 pm

(I) $E_{2}$ can have $(σ_{2 p})^{2} (π_{2 p})^{4} (π^{*}_{2 p})^{2}$ configuration

(II) $q = +$ ve value

(III) $E_{2}^{q}$ has more antibonding electron

(IV) Bond order of $E_{2} > E_{2}^{q}$

TestHub · Accepted Answer

Bond length/energy data implies E₂ is O₂ (121 pm, 496 kJ/mol) and E₂⁺ is O₂⁺ (112 pm, 643 kJ/mol).

(I) O₂ configuration: $(σ_{2 p})^{2} (π_{2 p})^{4} (π_{2 p}^{*})^{2}$ . Correct. (II) E₂⁺ is O₂⁺, so q = +. Correct. (III) O₂⁺ has fewer antibonding electrons than O₂. Incorrect. (IV) Bond order of O₂ (2) < O₂⁺ (2.5). Incorrect.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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