Chemistry - CHEMICAL BONDING Question with Solution | TestHub
ChemistryCHEMICAL BONDINGDipole MomentMedium2 minQB
ChemistryMediumnumerical
Passage / Comprehension
A hypothetical molecule AX₃Y has a tetrahedral arrangement around A. Steric repulsion from larger Y bends the three equivalent A-X bonds away from A-Y, so each X-A-Y angle θ = 114°. X and Y are more electronegative than A. Bond dipoles point from A outward: μ(A-X) = 1.80 D and μ(A-Y) = 1.20 D. A threefold axis passes through A-Y. A-X bond length = 1.11 Å. Given cos 114° = -0.4067, q = 1.5 × 10⁻¹⁹ C, 1 D = 3.33 × 10⁻³⁰ C·m, and cos β = √[(2 cos θ + 1)/3].
Let μnet be the net molecular dipole moment in debye. Calculate 10μnet and round to the nearest integer.
Answer:
1.00
Solution:
Using the supplied relation, cos β ≈ 0.24.
Resultant of three A-X dipoles = 3 × 1.80 × 0.24 = 1.296 D.
μnet = |1.296 - 1.20| = 0.096 D. 10μnet = 0.96 ≈ 1.
Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Dipole Moment
⏱ 2mℹ️ Source: QB
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