Intermolecular attractions influence boiling point, but the presence of one OH group is not a universal ranking rule. Use these supplied normal boiling points: CH₃OH65°C; C₂H₅OH78°C; propane−42°C; pro

Question

Intermolecular attractions influence boiling point, but the presence of one OH group is not a universal ranking rule. Use these supplied normal boiling points: CH₃OH65°C; C₂H₅OH78°C; propane−42°C; propanone56°C; n-pentane36°C; neopentane9.5°C; H₂S−60°C; H₂Se−41°C. How many proposed orders are INCORRECT: (i) ethanol>methanol; (ii) propane>propanone; (iii) neopentane>n-pentane; (iv) H₂Se>H₂S; (v) propanone>ethanol?

Answer:

3

Solution:

i and iv agree with the data. ii reverses−42<56, iii reverses9.5<36, and v reverses56<78. Hence3 are incorrect. Polarity, dispersion and molecular shape are relevant alongside hydrogen bonding.

TestHub · Accepted Answer

i and iv agree with the data. ii reverses−42<56, iii reverses9.5<36, and v reverses56<78. Hence3 are incorrect. Polarity, dispersion and molecular shape are relevant alongside hydrogen bonding.

Chemistry - CHEMICAL BONDING Question with Solution | TestHub

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