Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGMOTMedium2 minQB
ChemistryMediummultiple choice
Passage / Comprehension

As its name implies, MOLECULAR ORBITAL THEORY allocates electrons to molecular orbitals similar in many respects to atomic orbitals, but each containing two or more nuclei. To derive the ground state of the molecule, the electrons are placed in the available molecular orbitals, beginning with the orbital of lowest energy; each molecular orbital can accommodate a maximum of two electrons, provided their spins are opposed (Pauli's principle extended to molecules); and by filling as few orbitals as possible, and those of the lowest energy possible, we arrive at the electronic ground state.

molecule is diamagnetic and have mole bond energy and bond length , when molecule is ionized to unipositive ion :-

Options:(select one or more)

Answer:
B, C
Solution:

In N₂ (neutral), bond order = 3; in N₂⁺, one electron is removed from a bonding MO, so bond order decreases to 2.5.

Decrease in bond order leads to weaker bond and hence increased bond length, so (B) is correct.

Since energy is required to remove an electron from a strong bond, the overall energy change for forming N₂⁺ is greater than the ionization energy of isolated N atom, so (C) is correct.

Bond energy decreases (not increases), and N₂⁺ becomes paramagnetic, so (A) and (D) are incorrect.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:MOT
2mℹ️ Source: QB

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