Chemistry - CHEMICAL BONDING Question with Solution | TestHub

All four options (A, B, C, and D) have a non-zero dipole moment ($\mu \ne 0$).

For (A) and (B): The –OH and –SH groups are non-linear (bent) and rotate freely, creating unsymmetrical conformations where the individual dipoles do not cancel out.

For (C): The –NH₂ and –NF₂ groups are pyramidal and have vastly different group dipole moments that cannot mathematically cancel each other.

For (D): The two para-substituents (–OH and –SH) are entirely different groups, so their distinct dipole magnitudes and vectors fail to counteract one another.