Chemistry - CHEMICAL BONDING Question with Solution | TestHub

ChemistryCHEMICAL BONDINGBack bonding, Bridge bonding & odd electron moleculesHard2 minQB
ChemistryHardinteger

Use formal expanded-octet Lewis structures ONLY as a counting model; do not infer literal d-orbital π participation. In each entry consider every nonoxygen central atom. A species qualifies if at least one such centre has zero lone pairs and at least two formal double bonds. Count qualifying entries: SO₄²⁻ [two S=O]; SO₃²⁻ [one S=O]; PO₄³⁻ [one P=O]; ClO₄⁻ [three Cl=O]; ClO₃⁻ [two Cl=O]; SO₂Cl₂; HO–S(=O)₂–O–O–S(=O)₂–OH; NO₃⁻ [one N=O]. Apply the given contributor to each bracketed ion.

Answer:
4
Solution:

Sulfate, perchlorate, sulfuryl chloride and peroxodisulfuric acid qualify. Sulfite has a central lone pair and only one double bond; phosphate has only one; chlorate has a lone pair despite two; nitrate has only one. The zero-lone-pair test and the double-bond-count test must both be met. Count 4.

Stream:JEESubject:ChemistryTopic:CHEMICAL BONDINGSubtopic:Back bonding, Bridge bonding & odd electron molecules
⏱ 2mℹ️ Source: QB

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