Calculate number of pairs from the following pairs of species, in which underlined atoms of both are in same hybridisation? (i) B 2 H 6 , Al 2 Cl 6 (ii) ( SiO 3 2 − ) n , CO 3 2 −

Question

Calculate number of pairs from the following pairs of species, in which underlined atoms of both are in same hybridisation?

(i) $\underline{B}_{2} H_{6}, \underline{Al}_{2} Cl_{6}$

(ii) $(\underline{SiO}_{3}^{2 -})_{n}, \underline{CO}_{3}^{2 -}$

(iii) $AlCl_{4}^{-}, BH_{4}^{-}$

(iv) $\underline{XeO}_{3}, \underline{XeO}_{4}$

(v) $\underline{ClF}_{3}, ICl_{2}$

(vi) $NO_{2}^{+}, CN_{2}^{2 -}$

(vii) $\underline{N} (CH_{3})_{3}, \underline{N} (SiH_{3})_{3}$

TestHub · Accepted Answer

(i) B₂H₆: sp³, Al₂Cl₆: sp³ → same; (ii) (SiO₃²⁻)_n: sp³, CO₃²⁻: sp² → different.

(iii) AlCl₄⁻: sp³, BH₄⁻: sp³ → same; (iv) XeO₃: sp³, XeO₄: sp³ → same.

(v) ClF₃: sp³d, ICl₂⁻: sp³d → same; (vi) NO₂⁺: sp, CN₂²⁻: sp → same.

(vii) N(CH₃)₃: sp³, N(SiH₃)₃: sp² → different.

Same-hybridization pairs = (i), (iii), (iv), (v), (vi).

Hence, number of pairs = 5.

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