Chemistry - CHEMICAL BONDING Question with Solution | TestHub
Energy of 2p atomic orbitals and 2s atomic orbitals in oxygen atom are -15.85 eV and -32.38 eV respectively.
Number of species from given below which have higher ionization energy as compared to molecular oxygen.
Atomic oxygen, Atomic nitrogen, Molecular nitrogen, Atomic fluorine, Neon, Helium , Superoxide ion Find the value of Z ?
Answer:
Solution:
O₂'s electronic configuration:
An electron is removed from O₂'s highest occupied orbital. Given that the energy of the O atom's 2p orbital is , the ionization tendency of the given species is compared on this basis. First ionization energies:
O = , N = , N₂ = , F = , Ne = , He =
In O₂⁻, the extra electron is in the antibonding orbital, making it easier to remove an electron from O₂⁻ than from O₂.
Therefore, species with higher ionization energy are N, N₂, F, Ne, He, plus the intended comparison for O, giving:
